A constant horizontal pull acts on a sled on a horizontal frictionless ice pond. The sled starts from rest. When the pull acts over a distance $x,$ the sled acquires a speed $v$ and a kinetic energy $K.$ If the same pull instead acts over twice this distance,

the sled's speed will be $2v$ and its kinetic energy will be $2K.$

the sled's speed will be $2v$ and its kinetic energy will be $K\sqrt[\phantom{2}]{2}$

the sled's speed will be $v\sqrt[\phantom{2}]{2}$ and its kinetic energy will be $2K.$

the sled's speed will be $v\sqrt[\phantom{2}]{2}$ and its kinetic energy will be $K\sqrt[\phantom{2}]{2}.$

the sled's speed will be $4v$ and its kinetic energy will be $2K.$