A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on the same random sample of 12 cars. In particular, each car has one tire of each brand on its front wheels, with half of the cars chosen at random to have Brand 1 on the left front wheel, and the rest to have Brand 2 there. After all of the cars are driven over the standard test course for 20,000 miles, the amount of tread wear (in inches) is recorded, as shown in the table below.Could not fit all questions in picture but part c is asking for the test statistic. part d is asking to find the two critical values at the 0.10 level of significance. and part e is asking at the 0.10 level, can they consumer groups conclude that the mean tread wears of the brands differ? yes or no? please put what kind of test statistic and the degree of freedom for the problem

V Car 2 3 4 5 6 7 8 9 10 11 12 Brand 1 0.48 0.46 0,56 0.46 0.42 0.59 0.54 0.58 0.37 0.48 0.54 0.50 Brand 2 0.47 0.25 0.46 0.25 0.31 0.54 0.26 0.47 0.25 0.47 0.57 0.54 Difference (Brand 1 - Brand 2) 0.01 0.21 0.10 0.21 0.11 0.05 0.28 0.11 0.12 0.01 -0.03 -0.04 Send data to calculator Based on these data, can the consumer group conclude, at the 0.10 level of significance, that the mean tread wears of the brands differ? Answer this question by performing a hypothesis test regarding My (which is u with a letter "d" subscript), the population mean difference in tread wear for the two brands of tires. Assume that this population of differences (Brand 1 minus Brand 2) is normally distributed. Perform a two-tailed test. Then complete the parts below, Carry your intermediate computations to three or more decimal places and round your answers as specified. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H. O p H : X S H :0 (b) Determine the type of test statistic to use. Type of test statistic: (Choose one) O=0 030 020