A continuous footing is shown in the figure below.

Consider the following given information.

$=16\mathrm{.}81k\frac{N}{m^3}$

$c^{\text{'}}=27\mathrm{.}50k\frac{N}{m^2}$

${}^{\text{'}}=25$

$D_f=1\mathrm{.}02m$

$B=1\mathrm{.}22m$

factor of safety $=3k\frac{N}{m^2}.)$

$q_{\text{a}\text{l}\text{l}}=$

Your response differs from the correct answer by more than $10\%.$ Double check your calculations. $k\frac{N}{m^2}$