Question: A continuous RV,x has cumulative probability distribution function (CDF) defined as follows: FX(x)=kxfor0xa=[k/(ba)][bxx2/2]foraxb=1forx>b where a and b are arbitrary constants. Find the following given that,

follows: FX(x)=kxfor0xa=[k/(ba)][bxx2/2]foraxb=1forx>b where a and b are arbitrary constants. Find the following

A continuous RV,x has cumulative probability distribution function (CDF) defined as follows: FX(x)=kxfor0xa=[k/(ba)][bxx2/2]foraxb=1forx>b where a and b are arbitrary constants. Find the following given that, a=0.75 and b=1.25 and k= 0.15 - Expected value of the RV - Second moment of the RV distribution - Standard deviation of the RV distribution - Suppose the value of (a=0.75) represents the median of the RV: x of the CDF indicated. Find the corresponding values of the set, {b,k} - PDF, fx(x) of x over the specified range of RV Multiple-choice Answers: Choose the Correct Result 10.0660.10110.2821(2.05,0.671)=[k/(b+a)][bx]foraxb=0otherwise20.16010.09770.2684(2.25,0.667)=[k/(ba)][bx]foraxb=0otherwise30.1630.09120.2249(2.18,0.664)=[k/(ba)][b+x]foraxb=0otherwise40.2300.09100.2198(2.22,0.677)=[k/(ba)][bx]foraxb=0otherwisefX(x)=kfor0xa50.0650.10920.2521(2.19,0.678)=[k/(ba)][bx]foraxb=0otherwise

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