Question: A covered box is to be made from a rectangular sheet of cardboard measuring 15 inches by 24 inches. This is done by cutting out

 A covered box is to be made from a rectangular sheetof cardboard measuring 15 inches by 24 inches. This is done bycutting out the shaded regions of the figure and then folding on
the dotted lines. What are the dimensions x, y, and 2 thatmaximize the volume? _Ix+>~-I I .I' x = inches y = inchesz = inches A rectangle is constructed with its base on the

A covered box is to be made from a rectangular sheet of cardboard measuring 15 inches by 24 inches. This is done by cutting out the shaded regions of the figure and then folding on the dotted lines. What are the dimensions x, y, and 2 that maximize the volume? _Ix+>~-I I .I' x = inches y = inches z = inches A rectangle is constructed with its base on the diameter of a semicircle with radius 10 and with its two other vertices on the semicircle. What are the dimensions of the A . . I! rectangle With maximum area? ' h | The rectangle with maximum area has length D units and height D units. (Type exact answers, using radicals as needed.) Use Newton's method to estimate the solutions of the equation 6x2 + x 1 = 0. Start with x0 = 1 for the left solution and x0 =1 for the right solution. Find x2 in each case. Using Newton's method with x0 = 1, the third approximation, x2, to the left solution to 6X2 + x 1 = 0 is D. (Round to four decimal places as needed.) Using Newton's method with x0 = 1, the the third approximation, x2, to the right solution to 6x2 + x 1 = D is (Round to four decimal places as needed.)

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