A cross section of a sculpture can be modeled by a hyperbola (see figure). (-2, 13)...

Transcribed Image Text:

A cross section of a sculpture can be modeled by a hyperbola (see figure). (-2, 13) (2, 13) 8. (-1,0). (1, 0) 4 -3 -2 3 4 -4 -8 (-2, –13) (2,-13) (a) Write an equation that models the curved sides of the sculpture. (b) Each unit in the coordinate plane represents 1 foot. Find the width of the sculpture at a height of 8 feet. (Round your answer to three decimal places.) ft A cross section of a sculpture can be modeled by a hyperbola (see figure). (-2, 13) (2, 13) 8. (-1,0). (1, 0) 4 -3 -2 3 4 -4 -8 (-2, –13) (2,-13) (a) Write an equation that models the curved sides of the sculpture. (b) Each unit in the coordinate plane represents 1 foot. Find the width of the sculpture at a height of 8 feet. (Round your answer to three decimal places.) ft

Answer rating: 100% (QA)

Equalion of hyperbola is xh vertices are nta k and ha k 62 1 h4 1 2h 0hD0 ret given fi... View the full answer