Question: A cube with 100 dimensions 2 base cells: (a1, a2, ., a100 , count), (b1, b2, , b100 , count) Why is the amount of

A cube with 100 dimensions 2 base cells: (a1, a2, ., a100 , count), (b1, b2, , b100 , count)

Why is the amount of aggregate cells for having count >= 2 equal to 4, shouldn't it be 0 since you subtract out the overlapping cells? Please explain why it is not 0.

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