Question: A cylindrical vessel (circular cross-section) is floating in water ( ho ) = ( 1000(kg)/(m^(3))) . The inner diameter of the vessel is D=1m ,

A cylindrical vessel (circular cross-section) is floating in water

(\\\ ho

)

=

(

1000(kg)/(m^(3)))

. The inner diameter of the vessel is

D=1m

, its height is

H=2m

, the wall thickness is

\\\\delta =0.1m

and specific gravity of the vessel material is

SG_(v)=0.9

. The vessel contains a liquid of specific gravity

SG_(2)=1.2

. Determine the minimum depth

L_(min)

of the inner liquid above which the vessel would sink (i.e. all of the height

H

becomes submerged in water). Work in symbolic fashion as much as possible and then find numeric values.

A cylindrical vessel (circular cross-section) is
6. A cylindrical vessel (circular cross-section) is floating in water (=1000kg/m3). The inner diameter of the vessel is D=1m, its height is H=2m, the wall thickness is =0.1m and specific gravity of the vessel material is SGv=0.9. The vessel contains a liquid of specific gravity SG2=1.2. Determine the minimum depth Lmin of the inner liquid above which the vessel would sink (i.e. all of the height H becomes submerged in water). Work in symbolic fashion as much as possible and then find numeric values

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!