A displacement vector D is given as $40\mathrm{.}0$ m long at an angle of $60\mathrm{.}0$ degrees NORTH of EAST. The Dx component and the Dy component of the vector are

Dx $=+34\mathrm{.}6$ m$,$ Dy $=+20\mathrm{.}0$ m$.$

Dx $=+20\mathrm{.}0$ m$,$ Dy $=-34\mathrm{.}6$ m$.$

Dx $=+20\mathrm{.}0$ m$,$ Dy $=+34\mathrm{.}6$ m$.$

Dx $=-34\mathrm{.}6$ m$,$ Dy $=+20\mathrm{.}0$ m$.$

Dx $=+34\mathrm{.}6$ m$,$ Dy $=-20\mathrm{.}0$ m$.$