A driver attempts to performs a passing maneuver on a two$-$lane road. The driver is traveling $50$ mph while the vehicle that is being passed is traveling $35$ mph$.$ What is the calculated passing sight

distance for this condition?

Assume the following:

$$ t$1=4\mathrm{.}0$ seconds

$$ Assume that during initial maneuver distance the passing driver accelerates

linearly $($i$.$e$.$ Vavg$=($Vstart$+$Vend$)/2)$

$$ Assume that the acceleration rate is constant $($i$.$e$.$ a $=($Vend$-$Vstart$)/$t$)$

$$ Solve for t$2$ based on the same approach that was used in class $($both vehicles

are $22$ ft long and the clearance distances between the vehicles during lane

change are $20$ ft$)$

$$ Use the least conservative length for d$3,250$ ft$.$

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