A farsighted person cannot see objects clearly when they are closer than $53$ cm from their eyes.$$ Assuming they wear their glasses $1\mathrm{.}72$ cm in front of their eyes, what is the power of the corrective lens that will let them see an object $28\mathrm{.}3$ cm in front of their eyes clearly?

Enter your answer in units of diopters, or inverse meters.$$ For example, if your calculations result in a value of $1\mathrm{.}23$ D$,$ enter your answer as $1\mathrm{.}23.$