a) Fill the Table below. The time records in Table are in sec. Average ti 95%.Confidence %5 percent accuracy levelRequired sample size for the forthcoming time study (if required round up to multiple of 5) 2 3 4 5 RF 1,25 131 1 12 1,05 n= n'= ti = = 10,12 0,11 0,14 0,120,13 R0,23 0,550,931,25 1,6 b)Fill the Table below. The time records in Table are in sec. 2 3 5 sec/unit RF- RF 1.25 1,3 11 1.2 1,05 tn= 1 th 0,12 0,23 0,11 0,55 0,14 0,93 0,12 1.25 0,13 1,6 R R a) ti = Cycle time) (second/unit) = b)tn= {(Normal time) (second/unit)= c) Using a 25 percent job time allowance (Allowance Type 1 Style), what is the Tsip (Standard time) (second/unit)= . d) Determine the Q(standard output unit/Shr-day) = 2) Transform the given Allowance 0,25 (Allowance Type 1 Style-PDFI), into Allowance Type 2 as decimal 1) Using the transformed Allowance type 2, what is the TTD (Standard time) (second/unit) for this activity= 9) In respect to your answer about PDF2 (in f) calculate the new ( (Standard output unit/hr) = h) In respect to each Allowance (%) type, determine the corresponding time in minutes (for 9-hr shift) - On that same day (9-hour shift of interest), the worker completed 209032 work units. Determine the worker's performance level (P) expressed as decimal (%) = on that same day (9-hour shift of interest), it is known that the worker lost a total of 108 min due to personal time, rest breaks, and delays and completed 209032 work units. Determine the worker's performance level expressed as decimal Pw(%)=