A fish swimming in a horizontal plane has velocity = (4.00 + 1.00 ) m/s at...

Transcribed Image Text:

A fish swimming in a horizontal plane has velocity = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is r = (16.0 2.00 ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (21.0 - 1.00 ) m/s. (a) What are the components of the acceleration of the fish? ax ay = = m/s m/s (b) What is the direction of its acceleration with respect to unit vector ? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? x = m y = m In what direction is it moving? counterclockwise from the +x-axis A fish swimming in a horizontal plane has velocity = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is r = (16.0 2.00 ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (21.0 - 1.00 ) m/s. (a) What are the components of the acceleration of the fish? ax ay = = m/s m/s (b) What is the direction of its acceleration with respect to unit vector ? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 30.0 s? x = m y = m In what direction is it moving? counterclockwise from the +x-axis