A five-sided closed field traverse has the following distances in meters: AB = 51.766, BC= 26.947,...

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A five-sided closed field traverse has the following distances in meters: AB = 51.766, BC= 26.947, CD= 37.070, DE = 35.292, EA = 19.192. The adjusted angles are as follows: A= 101°03'19", B = 101°41'49", C= 102°22'03", D=115 57'20". E = 118°55'29". The bearing of AB is N 75°05'30" E. BC is in the SE quadrant. (a) Compute the bearings or the azimuths. (b) Compute the latitudes and departures. (c) Determine the linear error of closure and the accuracy ratio. A five-sided closed field traverse has the following distances in meters: AB = 51.766, BC= 26.947, CD= 37.070, DE = 35.292, EA = 19.192. The adjusted angles are as follows: A= 101°03'19", B = 101°41'49", C= 102°22'03", D=115 57'20". E = 118°55'29". The bearing of AB is N 75°05'30" E. BC is in the SE quadrant. (a) Compute the bearings or the azimuths. (b) Compute the latitudes and departures. (c) Determine the linear error of closure and the accuracy ratio.

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a Let WCB be whole circle bearingTherefore Bearing of AN750530 WCB of B 1807505301014149 1532341 Bea... View the full answer