A:) For a standard normal distribution (using the normal distribution table), find P(0.96

The normal distribution table gives the decimal area between z=0.96z=-0.96 and z=2.93z=2.93 as P(0.96

Converted to percent (%), the percent of data values between z=0.96z=-0.96 and z=2.93z=2.93 is P(0.96

B:)Using your standard normal distribution table, find the z-score cc such that: P(z

C:)The heights of adult men in America are normally distributed, with a mean of 69.2 inches and a standard deviation of 2.68 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.4 inches and a standard deviation of 2.57 inches. a) If a man is 6 feet 3 inches tall, what is his z-score, rounded to two decimal places? z=z= b) What percentage (%) of men are SHORTER than 6 feet 3 inches? Round to nearest tenth of a percent. % c) If a woman is 5 feet 11 inches tall, what is her z-score, rounded to two decimal places? z=z= d) What percentage (%) of women are TALLER than 5 feet 11 inches? Round to nearest tenth of a percent. % e) Who is relatively taller: a 6'3" American man or a 5'11" American woman?

• The 5-foot 11-inch American woman is relatively taller because she has a higher z-score than the 6-foot 3-inch American man.
• The 6-foot 3-inch American man is relatively taller because he has a higher z-score than the 5-foot 11-inch American woman.
• The 5-foot 11-inch American woman is relatively shorter because she has a higher z-score than the 6-foot 3-inch American man.
• The 6-foot 3-inch American man is relatively shorter because he has a higher z-score than the 5-foot 11-inch American woman.