Question: A force F ( x ) = ( - 4 . 0 x 2 + 8 . 0 x ) N h a t (

A force F(x)=(-4.0x2+8.0x)Nhat(i) acts on a particle as it moves along the x-axis.
Part (a)
How much work, in joules, does the force do on the particle as it moves from x=2.02m to x=5.11m?
W=
J
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Part (b)
If this force is a conservative force, what is the change in the potential energy, in joules, of the particle?
A force F ( x ) = ( - 4 . 0 x 2 + 8 . 0 x ) N h a

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