Question: A forceF ( x ) = ( 4 . 0 x 2 + 5 . 0 x ) Nacts on a particle. ( a )

A forceF(x)=(4.0x2+5.0x)Nacts on a particle. (a) How much work (in J) does the force do on the particle as it moves fromx=7.0mtox=9.0m?1(b) Picking a convenient reference point of the potential energy to be zero atx=0, find the potential energy for this force. (Use the following as necessary:x. AssumeU(x)is in joules andxis in meters. Do not include units in your answer.)\[ u(x)=-\frac{4}{3} x^{3}+\frac{5}{2} x^{2}\]

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