Question: A function j ( x ) is continuous everywhere except at x = 2 and has the following properties. ( 5 points ) lim x

A function j(x) is continuous everywhere except at x=2 and has the following properties. (5 points)
limxj(x)=-1 and limz-j(x)=-1
limx2-j(x)= and limx2+j(x)=-
j(0)=0,j(1)=1,j(3)=-3,j(4)=-2
j'(x)>0on(-,2)(2,)
j''(x)>0on(-,2)
j''(x)0on(2,)
A function k(x) is continuous on (-,-2)(-2,) and has the following properties. (6 points)
limxk(x)=1 and limx-k(x)=-
limx-2-k(x)= and limx-2+k(x)=-
k(-4)=0,k(0)=0,k(4)=6,k(7)=4
k'(x)>0on(-,-2)(-2,4)
k'(x)0on(4,)
k''(x)>0on(-,-2)(7,)
k''(x)0on(-2,7)
A function j ( x ) is continuous everywhere

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!