A gas mixture contains only $He$ and $N_2,$ has a total pressure of $1\mathrm{.}46$atm, and contains

$13$ mol of gas. If the partial pressure of $He$ is $0\mathrm{.}41$atm, how many moles of $He$ are in

the mixture?

Answer:

If you ever want to do some 'chemistry' with little kids, baking soda and vinegar is an

old standby. This reaction is good for volcanoes, rockets, fizzy paints, or just a giant,

foaming food coloring mess. Always a good time. Sodium bicarbonate and acetic

acid react to form sodium acetate, carbon dioxide, and water based on the following

equation.

$NaHC{O}_{3(s)}+H{C}_2{H}_3{O}_{2(aq)}Na{C}_2{H}_3{O}_{2(aq)}+C{O}_{2(g)}+H_2{O}_{(l)}$

A $15\mathrm{.}178g$ sample of $NaHC{O}_{3(s)}$ reacts with excess $H{C}_2{H}_3{O}_{2(aq)}.$ The carbon dioxide

produced is collected over water. The total volume of wet gas collected is

$L$ at $25\mathrm{.}3C$ and $683$ torr. The vapor pressure of water at this

temperature is $19$ torr.

Write your answer as $1\mathrm{.}23L$