Question: (a) Given that my foldr::b-> (a->b->b)->[a]-> b give the type of f in: f = myfoldr id g where g a h x = h

(a) Given that my foldr::b-> (a->b->b)->[a]-> b give the type of

(a) Given that my foldr::b-> (a->b->b)->[a]-> b give the type of f in: f = myfoldr id g where g a h x = h (a:x) Does the program type? Yes O No If yes, what is its most general type? Enter your answer here

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