Question: A graph G = (V, E) is identical to its breadth-first search tree TB = (V, E). Then, |E| = O(|V|). True or False? Present

A graph G = (V, E) is identical to its breadth-first search tree TB = (V, E). Then, |E| = O(|V|). True or False? Present a proof if it is true or a counterexample if it is false.

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