A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his property. His neighbor will pay for one third of the cost of materials on that side. Find the dimensions of the playground that will minimize the homeowner's total cost for materials. Follow the steps:(a) Let the width to be y and the length (the side along the boundary of his property) to be x, and assume that the material costs $1 per foot. Then the quantity to be minimized is (expressed as a function of both x and y) C= .(Use fraction for coefficients.)(b) The condition that x and y must satisfy is y= .(c) Using the condition to replace y by x in C, C can then be expressed as a function of x: C(x)= .(d) The domain of C is (,).(Use ``infty'' for .)(e) The only critical number of C in the domain is x= .(Keep 1 decimal place (rounded)). We use the Second-Derivative Test to classify the critical number as a relative maximum or minimum, or neither:At the critical number x= , the second derivative C''() is ---Select--- negative zero positive . Therefore at x= ,---Select--- the second derivative test has no conclusion the function has a relative minimum the function has a relative maximum .(f) Finally, plug x= into the condition of x and y we obtain y= .Therefore the length and width of the playground that will minimize the homeowner's total cost for materials are x= feet and y= feet, with the side along the boundary of his property equals feet.