Question: A homeowner wants to fence a rectangular play yard using 60 feet of fencing. The side of the house will be used as one side

A homeowner wants to fence a rectangular play yard using 60 feet of fencing. The side of the house will be used as one side of the rectangle. Find the dimensions for which the area is a maximum. (did i solve correctly?)

p=2L+2W

60=2L+2W

A=L*W

A=(30-W)-W

30=L+W

30-W=L

L=30-15

L=15

A=-W+30W

WIDTH=-30/2(-1)=15 YARDS

A=-(15)+30(15)

A=-1*225+30(15)

A=-225+450

A= 225 >>>>Maximum Area

There for all sides = 15 which would = 60

The answer would be 15ft by 30ft

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