Question: A horizontal block - spring system with the block on a frictionless surface has total mechanical energy ( E = 5 5 . 1

A horizontal block-spring system with the block on a frictionless surface has total mechanical energy \( E=55.1\mathrm{~J}\) and a maximum displacement from equilibrium of 0.229 m.
(a) What is the spring constant?
-\(\mathrm{N}/\mathrm{m}\)
(b) What is the kinetic energy of the system at the equilibrium point?
55
\(\checkmark \mathrm{J}\)
(c) If the maximum speed of the block is \(3.45\mathrm{~m}/\mathrm{s}\), what is its mass?
\(\checkmark \mathrm{kg}\)
(d) What is the speed of the block when its displacement is 0.160 m ?
\(\checkmark \mathrm{m}/\mathrm{s}\)
(e) Find the kinetic energy of the block at \( x=0.160\mathrm{~m}\).
Your response is within \(10\%\) of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. J
(f) Find the potential energy stored in the spring when \( x=0.160\mathrm{~m}\).
Your response is within \(10\%\) of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. J
(g) Suppose the same system is released from rest at \( x=0.229\mathrm{~m}\) on a rough surface so that it loses 15.1 J by the time it reaches its first turning point (after passing equilibrium at \( x=0\)). What is its position at that instant?
A horizontal block - spring system with the block

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