Question: A horizontal force, F = 65 N, and a force, F = 11.6 N acting at an angle of to the horizontal, are applied
A horizontal force, F = 65 N, and a force, F = 11.6 N acting at an angle of to the horizontal, are applied to a block of mass m = 3.4 kg. The coefficient of kinetic friction between the block and the surface is = 0.2. The block is moving to the right. Randomized Variables F = 65 N F2 = 11.6 N m = 3.4 kg F A 50% Part (a) Solve numerically for the magnitude of the normal force, Fin Newtons, that acts on the block if = 30. FN= k m 0 Otheexpertta.com Grade Summary Deductions Potential 0% 100% O 50% Part (b) Solve numerically for the magnitude of acceleration of the block, a in m/s, if 0 = 30. a = A block of mass m = 11 kg rests on an inclined plane with a coefficient of static friction of = 0.17 between the block and the plane. The inclined plane is L = 6.8 m long and it has a height of h = 3.35 m at its tallest point. DA 25% Part (a) What angle, 0 in degrees, does the plane make with respect to the horizontal? 0= 0 m Otheexpertta.com Grade Summary Deductions Potential 0% 100% A block of mass m = 11 kg rests on an inclined plane with a coefficient of static friction of u, = 0.17 between the block and the plane. The inclined plane is L = 6.8 m long and it has a height of h = 3.35 m at its tallest point. A 25% Part (a) What angle, in degrees, does the plane make with respect to the horizontal? A 25% Part (b) What is the magnitude of the normal force, Fyin newtons, that acts on the block? A 25% Part (c) What is the component of the force of gravity along the plane, Fgx in newtons? DA 25% Part (d) Will the block slide? O Yes O There is not enough information. O No 0 m Otheexpertta.com Grade Summary Deductions Potential 0% 100%
Step by Step Solution
3.49 Rating (149 Votes )
There are 3 Steps involved in it
Q1 Part a Answer Magnitude of Normal Force 3912 N Part b An... View full answer
Get step-by-step solutions from verified subject matter experts
