A horizontal pipe with water flowing through it has a circular cross section that varies in diameter. The diameter at the wide section is $5$ times the diameter at the narrow section.

Part A

If the rate of flow of the water in the narrow section is $15\mathrm{.}0$ L$/$minL$/$min$,$ the rate of flow of the water in the wide section is

$0\mathrm{.}60$ L$/$minL$/$min$\mathrm{.}3\mathrm{.}0$ L$/$minL$/$min$\mathrm{.}15\mathrm{.}0$ L$/$minL$/$min$\mathrm{.}60\mathrm{.}0$ L$/$minL$/$min$\mathrm{.}240$ L$/$minL$/$min$.$