A lab instructor performs a demonstration where a current$-$carrying wire is made to levitate. The wire has a mass per unit length of $0\mathrm{.}520\frac{g}{c}m$ and carries a current of $2\mathrm{.}72$ A horizontally to the south. Find the magnitude and direction of the minimum magnetic field needed to lift this wire vertically upward. $($Enter the magnitude in T$.)$

magnitude

What is the formula for the magnetic force on a current$-$carrying wire? If the wire levitates $($without accelerating$),$ how should this force be related to the weight of the wire? Using this relationship, can you solve for the magnetic field strength in terms of the mass per unit length? Be careful with unit conversions. T

direction