Question: A liquid layer separates two plane surfaces as shown. The lower surface is stationary; the upper surface moves downward at constant speed, V , starting

A liquid layer separates two plane surfaces as shown. The lower surface is stationary; the upper surface moves downward at constant speed, V, starting from a separation of b at time t=0. The moving surface has width 2L and is sufficiently long in the direction perpendicular to the figure that there is no flow in the z direction. The fluid is incompressible, of density , and frictional effects may be neglected.
(Use pa for the atmospheric pressure.)
Find the speed u(x,t) of the flow in the x direction in the gap under the chip assuming the flow is uniform in the y direction. [Hint: Consider the conservation of volume in a thin vertical rectangular region of height h lying between x and x+x.]
u(x,t)=
Write the acceleration of this flow in terms of u(x,t)[remember the flow is unsteady]:
Syntax hint: to input the derivative of u(x,t) w.r.t.x and t, write diff(u(x,t),x) and diff (u(x,t),t).
And hence find the acceleration of a fluid particle in the gap:
Find an expression for the pressure p(x,t).
p(x,t)=
Obtain an expression for the pressure force, per unit length in the z direction, that acts on the upper (moving) flat surface:
Syntax hint: where not specified, the answer should be expressed in terms of variables V,L,b,x,,pa and/or t.
A liquid layer separates two plane surfaces as

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