A long jumper just left the ground with an initial vertical velocity of $4\mathrm{.}25\frac{m}{s}$ and an initial horizontal velocity of $7\mathrm{.}36\frac{m}{s}.$ At the highest point in the trajectory before landing, the jumper's vertical velocity will be $q,.($ignore the influence of air resistance$)$

$-9\mathrm{.}81\frac{m}{s}2$

$0\frac{m}{s}$

Not enough information is provided to answer the question.

$7\mathrm{.}36\frac{m}{s}$

$4\mathrm{.}25\frac{m}{s}$