A $m=1\mathrm{.}00kg$ block starts from rest at the top of a $d=30\mathrm{.}0m$ long $31\mathrm{.}0$ incline. After sliding down the incline, the block's kinetic energy at the bottom is $141$ J $.$ How much work is done by friction?

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Par $1+$

Give an algebraic expression for finding the initial mechanical energy in terms of the block's mass $(m),$ the gravitational acceleration $(g),$ the amgle of the incline $(),$ and the length of the incline $(d).$

$($Enter $$ as theta$)$

$E_1=$

Your answer is interpreted as follows:

mgdsin$()$

$$ Coned answer, well done.

Pan $2$

How much work is done by friction?

Incrared answer