Question: A mass m A = 1 . 4 k g , moving with velocity vec ( v ) A = ( 3 . 8 hat

A mass mA=1.4kg, moving with velocity vec(v)A=(3.8hat(i)+4.0hat(j)-2.0widehat(k))ms, collides with mass mB=3.8kg, which is initially at rest. Immediately after the collision, mass mA=1.4kg is observed traveling at velocity
Find the velocity of mass mB after the collision. Assume no outside force acts on the two masses during the collision.
Enter the x,y, and z components of the velocity separated by vec(v)A'=(-2.0hat(i)+3.6widehat(k))ms. commas. Express your answer to two significant figures.
 A mass mA=1.4kg, moving with velocity vec(v)A=(3.8hat(i)+4.0hat(j)-2.0widehat(k))ms, collides with mass mB=3.8kg,

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Physics Questions!