Question: A mass (M_(1) ) = ( 7.5(kg)) is connected by a light cord to a mass (M_(2) ) = ( 16.7(kg)) which slides on a
A mass
(M_(1))
=(
7.5(kg))is connected by a light cord to a mass
(M_(2))
=(
16.7(kg))which slides on a smooth surface, as shown in the figure. The pulley (radius
=0.3m) rotates about a frictionless axle. The magnitude of the linear acceleration of
M_(1)is
0.81(m)/(s^(2)). What is the moment of inertia [in
kg^(**)m^(2)] of the pulley? (Use Newton's second law and torque, and
g=9.80(m)/(s^(2))).

A mass (M1=7.5kg) is connected by a light cord to a mass (M2=16.7kg) which slides on a smooth surface, as shown in the figure. The pulley (radius =0.3m ) rotates about a frictionless axle. The magnitude of the linear acceleration of M1 is 0.81m/s2. What is the moment of inertia [in kgm2 ] of the pulley? (Use Newton's second law and torque, and g=9.80m/s2 )
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