A mechanical system consisting of the thin rod, a solid disk, and a small solid puck all fixed together is rotating around a single frictionless axis at angular velocity $=1\mathrm{.}18\frac{\text{r}\text{a}\text{d}}{s}$ shown in the figure. The axis is located at the center of the disk and is at a distance $d=5\mathrm{.}34ml$ greater than $R$ away from the near end of the thin rod. The angular momentum of the rotating system is $A=65\mathrm{.}58kg*\frac{m^2}{s}.$ The mas a the rod is $M_{+}=2\mathrm{.}4kg$ and the length of the rod is $L=3\mathrm{.}89m,$ while the mass of the disk is $M_D=0\mathrm{.}46kg$ and the radius of $R=5\mathrm{.}15m.$ The small puck can be seen as a point particle of mass $m$ which is fixed onto the disk, a distance $r=4\mathrm{.}21ml.$ may from the pivot, as shown in the figure. What is the mass of the small puck of the puck$-$rod$-$disk system? Retain your answer to the cimal places.