A mixture is 10.0 mole% methyl alcohol, 75.0 mole% methyl acetate (C3H6O2) and 15.0 mole% acetic acid.

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A mixture is 10.0 mole% methyl alcohol, 75.0 mole% methyl acetate (C3H6O2) and 15.0 mole% acetic acid. Calculate the mass fractions of each compound.

What is the average molecular weight of the mixture?

What would be the mass (kg) of a sample containing 25.0 kmol of methyl acetate?

Related Book For answer-question

Thermodynamics An Engineering Approach

ISBN: 978-0073398174

8th edition

Authors: Yunus A. Cengel, Michael A. Boles

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Posted Date: Jul 17, 2021 03:49 AM

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A mixture is 10.0 mole% methyl alcohol, 75.0 mole% methyl acetate (C3H6O2) and 15.0 mole% acetic acid.

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Sol We convert percentages to fractions ie divide by 100 av... View the full answer

Thermodynamics An Engineering Approach

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