Question: { a n } a 1 = 1 2 , a n + 1 = a n - a n 2 ( newne ) (

{an}a1=12,an+1=an-an2(newne)(0): 1anan+12,(ninN**)
(2){an2} Sn
12(n+2)Snn12(n+1),(nN**)003
 {an}a1=12,an+1=an-an2(newne)(0): 1anan+12,(ninN**) (2){an2} Sn 12(n+2)Snn12(n+1),(nN**)003

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