Question: A (n) algorithm always runs faster than a (n^2) algorithm. (True/False) If f(n) O(g(n)), then f(n) + g(n) (g(n)) (True/False) n (log n) (True/False) n^2

A (n) algorithm always runs faster than a (n^2) algorithm. (True/False)

If f(n) O(g(n)), then f(n) + g(n) (g(n)) (True/False)

n (log n) (True/False)

n^2 (nlogn)(True/False)

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