A new project is scheduled for implementation based on the network shown. The estimated activity times and manpower required for the project is as indicated in Table 1. Activity Immediate Predecessors Activity Activity Activity Manpower Expected Variance Standard Requirement Time (te) deviation (0) A B D E F G H Estimate Activity Times (weeks) a m b 6 8 10 7 9 11 4 6 8 6 8 16 2 5 8 2 6 10 6 7 14 2 4 6 (A) (B (C (D) (E) A,B B, C DE E, F (b) c) (d) (e) (1) (b) (c) (d) (e) (0 ACT A-3 ACT B = 5 ACT C=3 ACT D=4 ACT E=4 ACT F = 3 ACT G= 2 ACT H=2 Table 1 Construct the LS-LF Gantt chart and resource allocation diagram based on the schedule. * Upload your Gantt Chart and Resource Allocation Diagram for this question. Based on the LS-LF Gantt chart and resource allocation diagram, determine and justify if levelling required given that the manpower available is limited to eleven (11). The standard deviation of the project duration op is calculated as: Op= summation of the oof all activities in the critical path 2 a + 4m + b te = 6 Variance (o)=6) Project variance = Sum (variances of activities on critical path) Project standard deviation = Project Variance The normal variant Z may be calculated as: Z= D-Te Op Knowing Z, the probability, can be read from the Normal Distribution Table attached. Where interpolation from the table is required, the probability P value maybe derived as follows: Z-Z1 P= P1+ (P2 P1) Z2 - Z1 Where P is the probability value for Z and P2 is the probability value for Z2. To calculate the probability P value, for negative values of Z: P (for negative Z) = 1 - P(for positive Z)