a) Now let's calculate the tangent line to the function {f(x) = {1-4x^{2}}} at x = 5.

By using f'(x) from part 2, the slope of the tangent line to f at x=5 is f'(5)=

b) The tangent line to f at x=5 passes through the point (5,f(5))=

-on the graph of f. (Enter a point in the form (2, 3) including the parentheses.)

c) An equation for the tangent line to f at x=5 is y=

Note: F(x) from part 2 is -8