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A parallel$-$plate capacitor has been connected to a battery for a very long time, as shown in the figure. Use the definition of capacitance $\backslash ($ C$=$Q $/$ V $\backslash )$ where $\backslash ($ C $\backslash )$ is the capacitance, $\backslash ($ Q $\backslash )$ the charge on the capacitor, and V the voltage across the capacitor, to guide your thinking as you answer the following three questions.

While still connected to the battery, the plates of the capacitor are moved further apart. When this happens;

The voltage across the capacitor, V

The capacitance of the capacitor, C

The charge on the capacitor, q

a$)\backslash ($ v $\backslash )$ : increases

C: remains the same

Q: decreases

b$)$ v : decreases

C: remains the same

Q: decreases

C$)$ v : decreases

C: remains the same

Q: increases

d$)$ V : remains the same

C: decreases

Q: decreases