Question: A parallel plate capacitor whose capacitance is 13.5 pF is charged by a battery to a potential difference V= 12.5 V between its plates.
A parallel plate capacitor whose capacitance is 13.5 pF is charged by a battery to a potential difference V= 12.5 V between its plates. The battery is disconnected, and a porcelain slab (k= 6.5) is slipped between the plates. a) What is the potential energy of the capacitor before the insertion of the slab? b) What is the potential energy after the slab inserted
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