A parallel$-$plate capacitor with plate area A and plate separation d has a capacitance of $4$ uf with the e gap between the plates unfilled. The gap is then filled with two dielectric materials, one with dielectric constant $2$ and the other one with dielectric constant $6.$ Each slab of dielectric has area A and thickness $12,$ the layering of the dielectrics resulting in the gap being completely filled. Which of the following combinations of capacitors will have the same capacitance as the newly filed parallel plate one?

$4.$ two capacitors in parallel, one with capacitance of & $$F and the other with capacitance of $24$F

two capacitors in series, with capacitance off and the other with capacitance of $24$

c$.$ two capacitors in parallel, one with capacitance of $16$F and the other with capacitance of $48$F

Od two capacitors in series, one with capacitance of $16$ uF and the other with capacitance of $48$F