A parallel-plate capacitor is to be constructed by using, as a dielectric, rubber with a dielectric constant of 3.20 and a dielectric strength of 15.0 MV/m. The capacitor is to have a capacitance of 1.60 nF and must be able to withstand a maximum potential difference of 4.00 kV.

Part A-What is the minimum area the plates of this capacitor can have? Express your answer in meters squared.

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To find the minimum area the plates of the capacitor can have we can use the formula for the capacit... View the full answer