A particle has a charge of $+4$e$.$ What is the magnitude of the electric field at a distance

of $2\mathrm{.}0$ m from the center of the particle? $($k $=1/4$$0=8\mathrm{.}99109$ N $$ m$2/$C$2,$ e $=1\mathrm{.}6010-19$ C$)$

Answer. $1\mathrm{.}410-9$ N$/$C