A particle moves along thex

-axis so that its position at timet>0

is given byx(t)=t^29/3t^2+8

Show that the velocity of the particle at timet

is given byv(t)=70t/(3t^2+8)^2

Is the particle moving toward the origin or away from the origin at timet=2? Give a reason for your answer.

The acceleration of the particle is given by a(t)

create an expression fora(t) and find the value ofa(2)

What position does the particle approach ast

approaches infinity?