A particle that is moving in an xy plane has a position vector given by i...

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A particle that is moving in an xy plane has a position vector given by i = (3.00t3 – 6.00t)î + (7.00 – 8.00t*)j, where i is measured in meters and t is measured in seconds. For t = 3.00s, in unit-vector notation, find (a)F , (b)ỹ, and (c) ä. (d) Find the angle between the positive direction of the x axis and a line that is tangent to the path of the particle at t = 3.00 s? A particle that is moving in an xy plane has a position vector given by i = (3.00t3 – 6.00t)î + (7.00 – 8.00t*)j, where i is measured in meters and t is measured in seconds. For t = 3.00s, in unit-vector notation, find (a)F , (b)ỹ, and (c) ä. (d) Find the angle between the positive direction of the x axis and a line that is tangent to the path of the particle at t = 3.00 s?

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Solution Given 7 300t3 600ti 700 800t3 a Substituting t 3 s 7 300 x ... View the full answer