A particle travels along a straight line with a velocity v = (12)(3t+2) m/s, where r...
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A particle travels along a straight line with a velocity v = (12)(3t+2) m/s, where r is in seconds [or v=5 +814]. Initially the particle is located 4 m to the left of the origin O. 1) Find the acceleration when t = 2s. Is the particle decelerating at that time? Why? Does the particle change its initial direction of motion? Explain. Determine the total distance traveled by the particle in t = 6 s. 0 S A particle travels along a straight line with a velocity v = (12)(3t+2) m/s, where r is in seconds [or v=5 +814]. Initially the particle is located 4 m to the left of the origin O. 1) Find the acceleration when t = 2s. Is the particle decelerating at that time? Why? Does the particle change its initial direction of motion? Explain. Determine the total distance traveled by the particle in t = 6 s. 0 S
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To find the acceleration when t 2 seconds we need to differentiate the velocity function v with resp... View the full answer
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