Question: A particle's position as a function of time is given by x(t) = 0.25 cos(39.5 t) (m) as it undergoes simple harmonic motion. Calculate the

A particle's position as a function of time is given by x(t) = 0.25 cos(39.5 t) (m) as it undergoes simple harmonic motion. Calculate the amplitude of the particle's motion, in m.

The equation of motion of a particle is given by -308 x = 1.64 a, where x is the position of the particle in m, and a is the acceleration of the particle in m/s². This equation has a form that will result in the particle undergoing simple harmonic motion. Calculate the period of that motion, in s.

The equation of motion of a particle is given by -243 x + 2,649 = 1 a, where x is the position of the particle in m, and a is the acceleration of the particle in m/s². This equation has a form that will result in the particle undergoing simple harmonic motion. Calculate the equilibrium position of this particle, in m.

A particle's position as a function of time is given by x(t) = 1.7 sin(85.9 t) (m) as it undergoes simple harmonic motion. Calculate the period of the particle's motion, in s.

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