Question: A particle's position as a function of time is given by F = (5.1m + 1.15%?) + (6.08%t + 0.53%3); S S' (The input below



A particle's position as a function of time is given by F = (5.1m + 1.15%?) + (6.08%t + 0.53%3); S S' (The input below will accept answers with no more than 1% variation from the correct value.) What is the angle between the particle's velocity and acceleration vectors at 1', = 1.075? degrees A ball of mass M : 1.92kg is moving in a circle of radius R = 2.88131 at constant speed. The ball takes t = 3.675 to go around a complete circle. (The input below will accept answers with no more than 1% variation from the correct value.) What is the magnitude of the acceleration this ball experiences? 2 S2 A ball of mass m = 2.62kg has its position vector given as r(t) = Rcos(wt + $)i + Rsin(wt + $)j The numerical values of the parameters are R = 0.89m, w = 1.36s-1, and d = 0.62. (The input below will accept answers with no more than 1% variation from the correct value.) What is v at t = 1.42s? m S S
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