Question: A particle's position is given by x = 13.0 - 12.00 t + 3 t 2 , in which x is in meters and t

A particle's position is given by x = 13.0 - 12.00t + 3t2, in which x is in meters and t is in seconds. (a) What is its velocity at t = 1 s? (b) Is it moving in the positive or negative direction of x just then? (c) What is its speed just then? (d) Is the speed increasing or decreasing just then? (Try answering the next two questions without further calculation.) (e) Is there ever an instant when the velocity is zero? If so, give the time t; if not, answer "0". (f) Is there a time after t = 3 s when the particle is moving in the negative direction of x? If so, give the time t; if not, answer "0".

(a) Number

Type your answer for part (a) here

Units

Choose your answer for part (a) here NWkgm/ssJm/s^2degreesm

(b)

Choose your answer for part (b) here positivenegative

(c) Number

Type your answer for part (c) here

Units

Choose your answer for part (c) here m/sdegreessWNJm/s^2mkg

(d)

Choose your answer for part (d) here increasingdecreasing

(e) Number

Type your answer for part (e) here

Units

Choose your answer for part (e) here m/s^2kgdegreesNWJsm/sm

(f) Number

Type your answer for part (f) here

Units

Choose your answer for part (f) here mkgdegreesWJm/ssm/s^2N

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!