Question: A particle's position is given by x = 13.0 - 12.00 t + 3 t 2 , in which x is in meters and t
A particle's position is given by x = 13.0 - 12.00t + 3t2, in which x is in meters and t is in seconds. (a) What is its velocity at t = 1 s? (b) Is it moving in the positive or negative direction of x just then? (c) What is its speed just then? (d) Is the speed increasing or decreasing just then? (Try answering the next two questions without further calculation.) (e) Is there ever an instant when the velocity is zero? If so, give the time t; if not, answer "0". (f) Is there a time after t = 3 s when the particle is moving in the negative direction of x? If so, give the time t; if not, answer "0".
| (a) | Number | Type your answer for part (a) here | Units | Choose your answer for part (a) here NWkgm/ssJm/s^2degreesm |
| (b) | Choose your answer for part (b) here positivenegative | |||
| (c) | Number | Type your answer for part (c) here | Units | Choose your answer for part (c) here m/sdegreessWNJm/s^2mkg |
| (d) | Choose your answer for part (d) here increasingdecreasing | |||
| (e) | Number | Type your answer for part (e) here | Units | Choose your answer for part (e) here m/s^2kgdegreesNWJsm/sm |
| (f) | Number | Type your answer for part (f) here | Units | Choose your answer for part (f) here mkgdegreesWJm/ssm/s^2N |
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
