A physical pendulum of mass m$=3\mathrm{.}36$kg

is comprised of an odd shape that has a centre$-$of$-$mass a distance of d$=0\mathrm{.}555$m

from the pivot point. The pendulum is displaced from equilibrium to $-10\mathrm{.}55\circ$

and released from rest at t$=0$s$,$ and at t$=0\mathrm{.}3$s the pendulum has reached $10\mathrm{.}55\circ$ for the first time.

What is the rotational kinetic energy of the pendulum at time t$=0\mathrm{.}474$s$?$

 

Answer rating: 100% (QA)

To figure out the rotational kinetic energy of the pendulum at time t0474s we need to first determin... View the full answer